a physics ?

Question

A particle that has a mass of 2.28x10^-22kg and a charge of 3.29x10^-22C is traveling through space at 2.40x10^8m/s and encounters a magnetic field with an intensity of 2.41T. The particle is moving perpendicular to the field. If the particle's velocity remains constant, what will be the radius of curvature of its path?

just mainly need the equation to solve it, the book I'm using sucks but any help much appriciated :)

i used those formulas too and got something that looked right but the answer was....

6.9X10^7m

and I have no idea how to get that...the book gave me same equations but apparently they the books sucks and the questions are...wtf

Answer 1

F=qvB force due to field on the charge

But curve curves so it sees a centripital force of F = mv^2/r where r = radius of curvature. If teh charge doesn't change speed teh two forces must be equal:

qvB = mv^2/r ---> r = mv/(qB)

Answer 2

The two equations are

Force = B*Q*v
(B=magnetic field strength, Q=charge, v=perpendicular speed)

(this is normally a vector equation but it is simplified because it is perpendicular)

and

Force = m (v^2) /r
(m=mass, v=perpendicular speed, r=radius)

and these should be equal
so
B*Q*v = m (v^2) /r

edit: I plugged your numbers into the formula and got the same answer as your book. Must have been a calculator slip.

r = 2.28x10^-22 x 2.40x10^8m/s / (3.29x10^-22 x 2.41)
= 10^8 x 2.28 x 2.40 / (3.29 x 2.41)
= 6.901 x 10^7 m

Answer 3

so ap physics is purely somewhat complicated, and as continuously relies upon on the instructor as properly (is he/she a reliable instructor? lots or little artwork, etc...) additionally relies upon on what else you're taking once you're taking ap physics, if the different training are not complicated and you may concentration on the class, then it relies upon and it relies upon on you, and how the priority is for you, and how complicated you pick to artwork at it sorry if this would not help, yet there are a number of components...