Physics i can't figure this out please help thanks?

Question

A particle initially located at the origin has an acceleration of 2.00 m/s2 and an initial velocity of 0 = 8.00 m/s.
(a) Find the vector position at any time t (where t is measured in seconds).
( t i ) m
Find the vector velocity at any time t.
( + wrong check mark
The correct answer is not zero.t ) m/s

(b) Find the coordinates of the particle at t = 3.00 s.
x = m
y = m
Find the speed of the particle at this time.
m/s

Answer 1

s=(1/2)at² will give you the distance from the origin and
v=at will give you the radial velocity. It could be anywhere on the circle of radius s (since no direction was specified for the force vector causing the accelleration)

To get numerical values for the actual position, you need the angle (Φ) the force is acting from and the coordinates would be
x=s*cos(Φ)
y-s*sin(Φ)
where s is the distance (from the origin) that you calculated.
The velocity components (in x and y) would be found the same way.

HTH

Doug

Answer 2

angular momentum (whilst a physique rotates approximately an axis... the farther a mass is from the axis of rotation, the lesser or greater good that's to be in momentum or to proceed rotating that's why whilst discern skaters bounce and spin or in simple terms spin, they ought to convey their palms closer to them because of the fact mass is far less unfold or mass is in simple terms very close to to the axis of rotation, so the discern skater spins speedier...)