1) A rectangular swimming pool is 30m wide and 50m long. If 600m3 of water is added to the pool, what is the?

Question

increase in the height of the water level in centimetres ?

2) A rectangular box is 16cm long and 10cm wide. 960 1-cm cubes can fit into the box exactly. What is the height of the box ?

Answer 1

Question 1
Increase in volume = 600 m³
Increase in height = h m
30 x 50 x h = 600
h = 600 / 1500 m
h = 600 / 15 cm
h = 40 cm

Question 2
V = 960 cm ³
10 x 16 x h = 960
h = 960 / 160 cm
h = 6 cm

Answer 2

It takes 1500 m^3 to raise the level 1 meter.
If you add 600 m^3 to an empty pool, you have 6/15 of a meter of height - which is 40 cm.

The area of the box is 160 cm^2. If the volume is 960, the height is 8 cm.

Answer 3

1. assuming that 600m3 fills up the pool, the depth of the pool would be 600/1500 or 6/15, or that would be 0.40m or 40cm.

2. if the volume of the box is 960 cm3, the formula for volume is V = l*w*h ==> 960 = 16*10*h therefore the height of the box is 6 cm.

Answer 4

1) area of swimming pool=(30x50)m^2
=1500m^2
after adding the water too the pool, the volume of the water is 600m^3 ,therefore,
600m^3=height x area
600m^3=height x 1500m^2
height=(600/1500)m
height=0.4m=40cm


2) area of the rectangular = (16 x 10)cm^2
=160cm^2
volume of the rectangular = total volume of the cubes
160cm^2 x height = 960 x 1cm^3
height = (960/160)cm
=6 cm

Answer 5

(1) Area of the pool = Length x breadth
...................................= 50 x 30 = 1500 m²
Volume of water added= 600 m³
Increase in water level= Volume / area
......................................= 600 / 1500 = 0.4 m
......................................= 0.4 x 100 = 40 cms
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(2) Base area of the box = 16cm x 10 cm = 160 cm²
The volume of the box = 9601 cm³
The height of the box = Volume / Area
....................................= 9601 / 160 = 60.00625 cm
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