1).solve for x.
3x-2y=6
2). solve.
-3(x+1)=2(x-8)+3
2007-09-10 19:17:40 · 8 answers · asked by moni 1 in Science & Mathematics ➔ Mathematics
x=(2y+6)/3
-3(x+1)=2(x-8)+3
-3x-3=2x-16+3
-5x=-16+3+3
x=2
HTH
Doug
2007-09-10 19:27:24 · answer #1 · answered by doug_donaghue 7 · 0⤊ 0⤋
1.) What is the value of y??
3x= 2y +6
x = 2(y +3) divided by 3
2.) -3x -3 = 2x -16 +3
-3 +13 = 2x + 3x
10 = 5x
2 = x
2007-09-11 04:25:36 · answer #2 · answered by mlw_jha 1 · 0⤊ 0⤋
1. 3x-2y = 6
3x = 2y+6
x = 2(y+3) divided by 3
2. -3(x+1) = 2(x-8)+3
-3x-3 = 2x-16+3
-3x-3 = 2x-13
-3x = 2x-13+3
-3x = 2x-10
-3x-2x = -10
-5x = -10
x = 2
2007-09-11 10:06:39 · answer #3 · answered by Ricky 2 · 0⤊ 0⤋
in the first question you can take out x in terms of y, as:
3x-2y = 6
3x = 6+2y
x = (6+2y)/3
2....-3(x+1) = 2(x-8)+3
-3x - 3 = 2x - 16 +3
-3x -2x = -13 +3
-5x = -10
x = 2
2007-09-11 02:45:39 · answer #4 · answered by the_coolest_gal 2 · 0⤊ 0⤋
1) x in terms of y. You can't solve for x.
x = (6+2y)/3
2)
-3(x+1)=2(x-8)+3
-3x-3=2x-16+3
5x=10
x=2
2007-09-11 02:29:05 · answer #5 · answered by Dummberdor 2 · 0⤊ 0⤋
i don't reall understand the first question,
maybe it is like this..
3x-2y=6
3x= 2y-6
x= (2/3)y -2
as for the second question, it goes like this
-3(x+1)=2(x-8)+3
-3x-3= 2x -16 + 3
-5x = -10
x=2
hope this will help
2007-09-11 02:35:35 · answer #6 · answered by Fayth 3 · 0⤊ 0⤋
1. you need to know what y= first.
2. -3(x+1)=2(x-8)+3
-3x-3=2x-16+3
-3x-3=2x-13
10=5x
x=2
2007-09-11 02:26:07 · answer #7 · answered by Anonymous · 0⤊ 0⤋
The first one you cannot solve because there are two pronumerals in the equation.
2) x=2
2007-09-11 02:26:29 · answer #8 · answered by Anonymous · 0⤊ 0⤋