f(x)=1/(x+3) Find the Difference Quotient?

Question

Basically this is a problem I've spent a while working on, and I can't seem to get the right answer.

f(x)=1/(x+3)

^^^Is the function, and I'm supposed to find the difference quotient. We have not really gone over secant/tangent lines yet, so just simplify it in:
[f(x+h)-f(x)]/h

If you could show all your steps, that would be most helpful
Any help would be greatly appreciated.

Answer 1

i am not good at explaining mathematic in english so i just show you how i do it

f(x) = 1/(x+3)
f(x) = (x+3)^(-1)
f*(x) = (-x-3)^(-2)
f*(x) = 1/(-x-3)^(2)
f*(x) = 1/( + 6x +9)

hope this will help, and sorry if i am wrong because i don't really understand your question..

Answer 2

f (x) = (x + 3)^( - 1 )
f `(x) = (-1) (x + 3) ^( - 2 )
f `(x) = (-1) / (x + 3) ²