create the largest number you can.?

Question

using 1, 2, 3, 4
and....
using parentheses ( ), decimal point '.' , and a minus sign '-'

create the largest number you can.

* you may only use the numbers once, but may use the symbols as many times as you want.

Please help me out, this is really baffling.
thank you so much.

Answer 1

(-4.)(-3.)(-2.)(-1.)=24


is it ok



ok thanks

Answer 2

*IF* the usual way of writing exponents as a superscript is OK and doesn't count as "symbol use", as opposed to using a caret, then yes, exponents would give you the largest numbers. 4^(31^2) would give you a number that's 579 digits long. 2^(3^41) gives you something even bigger. Otherwise...

Are we required to use ANY of the symbols at all? Because it would seem to me "4321" would be as big as you can get, assuming you could group digits together.

If you can't group the digits together, then the next biggest number would be 4(3)(2)1.

If you can only use parentheses for grouping and not multiplication, then the next best one is 4 - (-3) - (-2) - (-1). Using minuses any other way would only give you a smaller value, as would using decimals at all.

Answer 3

without using exponents:

=4-(-3)-(-2)-(-1) = 10, I'm assuming those are the only symbols we can use.

If you can use multiplication this would be higher:

=(2-(-1))(3)(4) = 36

If you can go all the weird stuff everyone else is trying I think it is

(.1)^(-(3^42))

which is ridiculously large - over 10^20 digits
Note that (.1)^(-n) is the same as 10^n

Answer 4

if this isnt the riddle i thought i know it is, and ur answering on a sheet of paper by handwriting(or u're really good with signs/symbols thingy on a computer), u only need to make use of "power of" just alright. but i'm not good typing so i'll hv to use the "^"

2^(3^41)
=two to the power of [three to the power of 41]

BUT.....
riddle-wise, u arrange the digits into

3 . 1 4 2
=a pi(e?)

and what shape ur average pie is? and pi told u it's a merry, merry go round...a circle...there goes ur largest no!

a O=Zer0

Answer 5

One possibility is (1+2)^(3^4).

Answer 6

4 321

Answer 7

Can the numbers be used together? If so I'd say

4(32-.1)

Answer 8

2^(3^41) - 2 to power of 3 to power of 41

Answer 9

Zero

Answer 10

21^43


**no, Peter C has me beat

Answer 11

4321