in a reaction between magnesium and oxygen, the only product is 80.0 grams of magnesium oxide. how many grams of magnesium were burned?
2007-09-10 17:06:04 · 5 answers · asked by hii 1 in Science & Mathematics ➔ Chemistry
Start with your reaction
2 Mg + O2 = 2 MgO
Find the moles of MgO (mol wt=40)
From the equation, each mole of MgO requires 1 mole of Mg.
So multiply the number of moles by the g-at wt of Mg (24) to get your answer.
2007-09-10 17:10:01 · answer #1 · answered by cattbarf 7 · 0⤊ 0⤋
That's an easy question to answer. The formula of magnesium oxide is MgO, and the molecular mass is 40.3 grams per mole. 24.3 of those grams are magnesium, and 16 of those grams are oxygen. The proportion of magnesium in MgO is
24.3 / 40.3 = 0.603
so the amount of magnesium in 80 grams of MgO is
0.603 x 80 = 48.24 grams
2007-09-10 17:16:27 · answer #2 · answered by Anonymous · 0⤊ 0⤋
start with a balanced equation
2Mg+O2 --> 2MgO
so you start with 80g MgO x 1mol MgO/40.3g MgO x 2mol Mg/2mol MgO x 23.3 g/mol Mg/1 mol Mg = 46.3 g Mg
you cancel the units out to be left with grams for which you are asked and just multiply and divide.
2007-09-10 17:57:38 · answer #3 · answered by Anonymous · 0⤊ 0⤋
The Silver metallic is beside the point in this calculation because of the fact this is not any longer right now related to the reactant and product. Multiply 12.6gHNO3 situations conversion element (1molHNO3/sixty 3.018g) XCF (1molNO/4 molesHNO3) XCF (30.01 gNO/1molNO) = a million.50 g NO CF = Conversion element X = situations
2016-11-14 22:08:17 · answer #4 · answered by ? 4 · 0⤊ 0⤋
Okay okay--At Your Service Madame! Just first tell me what stoichiometry means and then I'll answer your question.
2007-09-10 17:09:18 · answer #5 · answered by richard d 3 · 0⤊ 0⤋