Can anyone help me answer this math question?

Question

Don is camping out by a clear mountain stream and decides to make some rice. The cooking directions asks for 1 quart of water, but Don had only a 7 quart jug and a 11 quart jug. Don hates dry rice and he hates sticky rice how can he measure to exactly 1 quart? By the way he can get as much water as he like and waste it

Answer 1

fill the 11qt
pour into 7 qt until full, then empty 7qt.
pour remaining 4 qt from 11 qt container into 7qt

fill 11qt again
fill 7qt from 11 qt container(will only need 3 more qt to do this)
empty 7 qt

fill 7 qt again from 11qt container (only 8qts left in this container)
then will have only 1 qt left in 11 qt container

Geezah's way works too, but mine requires less work :)

To Manjyomesando1 - Geezah changed his/her answer. Geezah originally wrote an answer that used 7*8-5*11=1

Answer 2

Fill the 7 qt jug with water and pour all into the 11 qt jug. Mark the level of 7 qt on the 11 qt jug.

Fill the 11 qt jug and pour into the 7 qt jug until it is full. Mark the level of 4 qt on the 11 qt jug. Dump out 7 qt. jug.

Fill the 11 qt jug to the 7 qt level. Pour into the 7 qt jug until the water in the 11 qt jug is at 4 qt. Mark the 3 qt. level on the 7 qt. jug. Dump out the 7 qt. jug.

Pour the rest of the water left in the 11 qt. jug into the 7 qt. jug until it reaches the 3 qt. level on the 7 qt. jug. There will be one quart left in the 11 quart jug.

Answer 3

Ah, the old "jug" problem. I'll use (x,y) to show how many quarts are in the seven-quart jug (x) and eleven-quart jug (y).

1) Fill the eleven-quart jug from the stream (0,11))
2) Dump the contents of the eleven-quart jug into the seven-quart jug (7,4)
3) Empty the contents of the seven-quart jug (0,4)
4) Dump the contents of the elevent-quart jug into the seven-quart jug (4,0)
5) Repeat steps 1 (4,11), 2 (7,8), and 3 (0,8).
6) Finally repeat step 1 again (7,1). There will now be exactly one quart in the eleven-quart jug.

Answer 4

fills the 11, pours 7 into the 7, leaving 4
empties the 7, transfers the 4 to the 7
refills the 11, transfers 3 to top up the 7, leaving 8
empties the 7, tops up again from the 11,
leaving 1 in the 11

Answer 5

no 2 answerers gave a distinct answer, q_midori...
all revolve around 2*11-3*7=1, that is filling 11q twice and pouring into 7q 3 times, leaving 1quart in 11q container.

to q_midori, sorry! and that's a painfully long process of getting just 1 quart if water, too!