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10. (5,4) and (7,4)

11. (2,6) and (-3, -4)

12. (-2,3) and (4,-6)

How do I do these?

2007-09-10 13:45:39 · 14 answers · asked by Kristen V 3 in Science & Mathematics Mathematics

I don't understand anything the people down tehre said!!

2007-09-10 13:53:22 · update #1

14 answers

rise
___
run

(rise over run, or the change in y over the change in x)
so,
10. 4-4/7-5= 0/2, so the slope is 0, so it is undefined.
11. 6+4/2+3=10/5=2, so the slope is 2
12. 3+6/-2-4=9/-6=3/-2=1 1/2, which is the slope

be care about the negative signs and which number u use first doens't matter, as long as y's are on top, and x's are on the bottom, and if u use one of the ordered pair numbers first, u still use that 1 first for the x's
i hope that helped! good luck!

2007-09-10 13:52:29 · answer #1 · answered by Anonymous · 0 0

rise over run:

Y2-Y1
_____
X2-X1

10. 4-4=0 and 7-5=2 so the slope would be 0/2 so it is flat, no slope...
11. -4 - 6= -10 and -3 - 2=-5 so the slope is -10/-5, simplify that into 2/1. a line that goes up
12. -6 - 3=-9 and 4 - -2=6 so the slope is -9/6, simplify that into -3/2, a line that goes down

2007-09-10 20:55:09 · answer #2 · answered by Anonymous · 0 0

In a line equation, we have what's called "slope-intercept" form.

The general equation is
y=mx+b

Where y and x are variables, m is the slope, and b is the y-intercept (the point where the line crosses the y axis).

To calculate slope, you do this equation:
m = (y2-y1)/(x2-x1)

In your first equation, you have these points:
(5,4) and (7,4)

x1 = 5, x2 = 7
y1 = 4, y2 = 4.

So do the equation.

m = (4-4)/(7-5)
m = 0/2
m = 0

You can do the others.

2007-09-10 20:53:19 · answer #3 · answered by Brian L 7 · 0 0

Use the change in slope formula:
y2 - y1; where (x2, y2) and (x1, y1)
---------
x2 - x1

10: (4 - 4)/ (7 - 5) = 0
11: (-4 - 6)/ (-3 - 2) = (-10)/(-5) = 2
12: (-6 - 3)/ (4- -2) = -9/ 6 = -3/ 2

Good luck with your homework =)

2007-09-10 20:55:06 · answer #4 · answered by xD you'll love me 2 · 0 0

10. (4-4)/(7-5) = 0 meaning that it is just a horizontal line in a linear equation

11. (6-(-4))/(2-(-3))

12. (-6-3)/(4-(-2))

basically the general equation for these is (y2-y1)/(x2-x1)

2007-09-10 20:52:39 · answer #5 · answered by kimbokrn 2 · 0 0

(4-4)/(7-5) = 0/2 = 0
(-4-6)/(-3-2) -10/-5 = 2
(-6-3)/4-(-2)) = -9/6 = -3/2

2007-09-10 20:54:46 · answer #6 · answered by ironduke8159 7 · 0 0

first graph it. on a cartisian plane. xy plane. then slope=

(y2-y1)/(x2-x1)

that is y sub 2 . like #10 has a slope of 0 because (4-4)/(7-5)=0

careful of the negitive signs!

2007-09-10 20:52:21 · answer #7 · answered by gonavy271 2 · 0 0

slope (m) = rise / run

m = [y1 - y2] / [x1 - x2]

10. m = [4 - 4] / [5 -7]
m = 0 / -2 (I believe this would be a horizontal line)

you could try the other two, simple plug in

2007-09-10 20:53:42 · answer #8 · answered by dontknowphysics 1 · 0 0

GENERAL FORMULA: (y2-y1)/(x2-x1)

10. (4-4)/(7-5) = 0/2 = 0

11. (-4-6)/(-3-2) = -10/-5 = -2

12. (-6-3)/(4--2) = -9/6 = -3/2

2007-09-10 20:55:24 · answer #9 · answered by Anonymous · 0 0

You would do Y^2-Y^1/ X^2-X^1

For example: (7-5)/ (4-4)= undefined

2007-09-10 20:52:20 · answer #10 · answered by Skeet Skeet Champ 3 · 0 0

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