Is my answer to this world problem correct?

Question

Given: V=(1/3)Bh, where B is the area of the base and height.

A pyramid has a rectangular base. Find the volume if the length and width of the base and and the height are three consecutive odd integers and x is the largest integer.

The answer I came up with:
(x^3 - 3x^2 + 2x)/3

If it's wrong can someone show me how to figure out this equation?

If it's consecutive odd numbers, it should be x-4, x-2, and x... but on an example my teacher put x-2 ,x-1, and x. So which one is right? xP

Answer 1

Three consecutive odd integer with x being the largest is x-2, x-4, and x.

The base is l * w so B = (x-2) * (x-4)

The height is x.

So V = ((x ) * (x-2) * (x-4))\3

:)

Answer 2

The volume of the pyramid is:

Let
L = length base
W = width base
h = height

Consecutive odd integers differ by two. So we have:

V = (1/3)x(x - 2)(x - 4) = (x³ - 6x² + 8x)/3

Answer 3

if x is height and largest integer then volume is
(1/3) * ((x-4)(x-2)) * x if x is odd then x-2 , and x-4 are the two lower odd numbers
1/3 * (x^2 -4x -2x +8) * x
= 1/3 * ( x^3 -6x^2 +8x)
(x^3-6x^2+8x)/3

x, x-1 , x-2 are consecutive integers but not odd or even
7,6,5 for example

Answer 4

I totally don't care to distribution polynomials but if you had

x * (x-2) * (x-4) * 1/3

then you're right. okay but i did it anyway and i got.
(x^3 -6x^2 + 8x) / 3

so who's wrong...?

Answer 5

WTF. :(
y and z come after x, dumbass. gosh.


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