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(243 ^ -1/3) ^ -3/5

is it
a) 27
b) -27
c) -3
d) 3

please show me how to do it

2007-09-10 13:26:28 · 9 answers · asked by Anonymous in Science & Mathematics Mathematics

9 answers

(243^-1/3)^-3/5

= 243^3/15

= (3^5)^3/15

= 3^15/15

=3^1

=3

Answer is ''d)''

2007-09-10 13:37:02 · answer #1 · answered by frank 7 · 0 0

243 ^ -1/3 = 1/ (the cube root of 243)
1/ (the fifth root of the answer we got in the last step) ^3

A negative exponent means to find the reciprocal or simply to divide 1 by the number.

A fraction as an exponent means find the exponent's denominator and that will be the root of the number then find the numerator of the exponent and use it like a normal exponent.

So the answer is 3

2007-09-10 20:42:17 · answer #2 · answered by Anonymous · 0 0

the answer is d.
When a number that is taken to an exponent is taken to another exponent, they are multplied together. So -1/3 is multiplied by -3/5. This gives you 1/5. So then its 243^1/5, which is 3.

2007-09-10 20:33:52 · answer #3 · answered by Anonymous · 0 0

(243^-1/3)^-3/5 =
243^1/5 (multiply the two exponents -1/3 * -3/5 = 1/5
Now take the 5th root of 243, which is 3

2007-09-10 20:34:55 · answer #4 · answered by Steve A 7 · 0 0

Since one exponent is inside the parentheses and the other is outside, you multiply the two. This makes it a lot simpler already, since the two negatives make a positive. Then it should be pretty easy to figure out which one of the choices multiplied by itself x number of times will equal the base number.

2007-09-10 20:35:58 · answer #5 · answered by The Babe is Armed! 6 · 0 0

[(243)^-(1/3]^(-3/5)
=[243]^(-1/3)(-3/5) (since (a^x)^y = a^(xy))
=[243]^(1/5)
=[3^5]^(1/5)
=[3]^[(5)*(1/5)]
=3^1
=3

2007-09-10 20:43:28 · answer #6 · answered by mohanrao d 7 · 0 0

I'm not sure how to do it by hand, but you could just type it into your calculator. (make sure you include the parentheses)

2007-09-10 20:33:22 · answer #7 · answered by Anonymous · 0 0

d

2007-09-10 20:34:09 · answer #8 · answered by ignoramus 7 · 0 0

What the hell are these> ^ ?

2007-09-10 20:33:52 · answer #9 · answered by Anonymous · 0 0

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