English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

A solid sphere having a volume of 1.00 m^3 fits tightly in a cubical box. What is the volume contained within the box?

2007-09-10 13:12:58 · 2 answers · asked by dontknowphysics 1 in Science & Mathematics Physics

2 answers

The volume of a sphere is 4/3(pi)r^3 and the volume of a cube with a dimension of 2r would be (2r)^3

So the sphere to cube ratio is (2r)^3/(4/3pi(r^3))

canceling r's other other parts we get that the cube will be 6/pi the size of the sphere in volume.

2007-09-10 13:22:34 · answer #1 · answered by rscanner 6 · 0 0

First: use the equation volume of sphere = 4/3 x pi x r^3 to find the radius of the sphere.

Second : double that radius to find one side of the cube.

Third: find the volume of the cube by multiplying the side by itself three times, i.e. V = s^3

2007-09-10 20:25:24 · answer #2 · answered by flandargo 5 · 0 0

fedest.com, questions and answers