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2007-09-10 13:08:37
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answer #1
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answered by Anonymous
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All right, you know that 9 = 3^2, right? So, you could rewrite the first term as (3^2)^(3/7). When you raise a power to a power, you multiply the exponents, so that simplifies to 3^(6/7).
Now you're multiplying two powers of 3, and so you can add the exponents:
3^(6/7) x 3^(1/7) = 3^(7/7) = 3^1 = 3
There ya go! Good luck!
2007-09-10 13:07:50
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answer #2
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answered by Lucas C 7
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If you can get the number being raised to the power to be the same then you can add the exponents. So
9^(3/7) = (3^2)^3/7 = 3^(6/7)
now you can add exponents since both have a base of 3 to get
3^(6/7 + 1/7) = 3^1 = 3
2007-09-10 13:06:55
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answer #3
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answered by rscanner 6
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Get the same base.
9 = 3^2
(3^2)^(3/7) * 3^(1/7)
3 to the 2 is brought to another exp. You can multiply them.
3^(6/7) * 3^(1/7)
You can now add the two exponents.
3^(7/7)
or simply, 3.
Check with google calculator --
(9^(3 / 7)) * (3^(1 / 7)) = 3
bam!
2007-09-10 13:10:05
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answer #4
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answered by ryuku32 3
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Note that 9 is 3 x 3
To multiply the same number with different exponents, you add the exponents.
So you have 3^3/7 x 3^3/7 x 3^1/7
Adding the exponents give 3/7 + 3/7 + 1/7 = 7/7 =1
So you get 3 ^ 1 = 3
:)
2007-09-10 13:06:37
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answer #5
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answered by ignoramus 7
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9^3/7 can be changed to (3^2)^3/7 which equals 3^6/7
Your problem is now 3^6/7 * 3^1/7=?
Have you got it from there?
2007-09-10 13:07:44
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answer #6
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answered by Paladin 7
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9^(3/7) x 3^(1/7)
9 = 3^2
(3^2)^(3/7) x 3^1/7
3^(6/7) x 3^1/7 = 3^1 = 3
2007-09-10 13:08:02
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answer #7
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answered by ChemistryMom 5
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9^3/7 *3^1/7=3^6/7* 3^1/7=3^(6/7+1/7) =3^1=3 ANS.
2007-09-10 13:07:38
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answer #8
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answered by Anonymous
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turn 3/7 into a decimal and you can take it from there.take 3 divided by 7.
and you get a decimal.
2007-09-10 13:10:04
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answer #9
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answered by ouryearishere 2
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9*9=81*9=179*3=532/7=76.
Multiply everything and divide the two.
2007-09-10 13:09:49
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answer #10
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answered by vanallenbelt1 2
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