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2x^2+3x-1, f(x+h)-f(x)/h, h is not = to zero

2007-09-10 11:35:49 · 1 answers · asked by ladylight 1 in Science & Mathematics Mathematics

1 answers

Do you mean {f(x+h)-f(x)} /h and let h approach zero?
If "yes", it would be the fundamental of derivative of the function f(x) and if f(x) = 2x^2+3x-1, the derivative would be 4x + 3.
Let me show you:
f(x+h)-f(x) = 2(x+h)^2+3(x+h) -1 - {2x^2+3x-1}
= 4xh + 2h^2 + 3h
Thus {f(x+h)-f(x)} /h = 4x + 2h + 3
When h approachs zero, the result approachs 4x + 3.
Have I answered your question?

2007-09-10 14:29:47 · answer #1 · answered by Hahaha 7 · 0 0

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