math question i dont get it at all?

Question

Chairs for a meeting are arranged in six rows. Each row has the same number of chairs.

a. What is the minimum possible number of chairs that could be in the room?

b. Suppose 100 is the maximum number of chairs allowed in the meeting room. What other number of chairs are possible?

Answer 1

If each row must have the same number of chairs, the minimum number of chairs that could be in the room would be 6, since each row must have at least 1 chair.

If the maximum number of chairs in the room is 100, then the other number of chairs possible would be any multiple of 6 up to 16, since 16 x 6 = 96 and 17 x 6 = 102, which is more than the maximum.

Answer 2

part a) I would say it depends on how u define a row. Does one chair in a row still make it a row?? if yes then 6 is the answer. If it takes at least 2 chairs to make a row then the answer is 12.

part b) u would have to take all composite numbers divisible by 6 (up to 100) so u could have 6, 12, 18, 24, 30, 36, 42, 48, 54, 60, 66, 72, 78, 84, 90, or 96

Answer 3

a. Unless you allow "rows of zero chairs", then there has to be at least one chair per row, so the minimum number is 6. Some people will say that a row is not a row unless there are at least 2 chairs in it (my dictionary defines row as a succession of things -- plural). In that case, the minimum number would be 12.
But a mathematician would accept rows of 1. And a set theorist might even accept rows of zero. But they are not in your class doing this problem...
So, go for 12 and explain why (a row must have two chairs to be a "succession of things" as stated in a dictionary).


b) the next multiple of 6 after 100 is 102 (6 rows of 17). After that you can have 108, 114, 120 (6 rows of 18, 19, 20). A fancier way of saying it is: 102 + 6k, where k is any non-negative integer (0, 1, 2, 3, 4...... forever).

Answer 4

a- six

b- 16 each row, 96 chairs total

Answer 5

would you class one chair as a row?

Answer 6

a. you need a minimum number divisible by 6

b. you need a maximum number divisible by 6 & less than 100