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A rocket sled has a ,mass of 4440 kg and is propelled by a solid-propellent rocket motor of 890,000-N thrust which burns for 3.9 sec.
a) what is the sled's average acceleration and max speed?
b) This sled has a max acceleration of 30g (30a). How can
that be considering the data given?
c) If the seld travels a distance of 1530m while attaining a top speed of 860 m/sec, what is its average acceleration? How did it attain that high a speed?

2007-09-10 10:32:19 · 2 answers · asked by DJ Ott 1 in Science & Mathematics Physics

2 answers

Initial mass Mi = 4440 kg. Max accel of 30 g implies final mass Mf = 890000/(30*g) = 3024 kg, so propellant mass = Mi-Mf =1416 kg. Specific impulse = 890000*3.9/1416 = 2451 n-s/kg = 250 kg(force)-s/kg = 250 "seconds". Exhaust velocity Vex = 2451 m/s.
a) Max (final) velocity v = Vex * ln(Mi/Mf) = 2451 * 0.3841 = 941 m/s. Average acceleration = v/t = 241.4 m/s^2 = 24.61 g.
b) The mass decreases as described above.
c) The distance and max-speed numbers given here describe a different system, either lower total impulse or different masses, as they disagree with the results above. With an unknown thrust and burn duration and time-varying mass, one cannot solve for average acceleration given distance and speed, and describe how it attained that high a speed.

2007-09-10 10:41:53 · answer #1 · answered by kirchwey 7 · 0 0

very obscure question devoid of information .. this relies upon on numerous parameters, and preliminary circumstances.. the pliability of the band in question comes into play too. choose greater information

2016-11-14 21:22:38 · answer #2 · answered by ? 4 · 0 0

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