Math question?

Question

A smart shopper bought 5 pairs of shorts and 8 tops for a total of $108. if the price of a pair of shorts was twice the price of a top, the nwhat was the price of each type of clothing.

Answer 1

the question should be solved by making this formula. the price for tops should be x, the price for shorts would be 2x.

5(2x) +8x =108
10x +8x =108
18x=108
x=6
this means Tops are $6 and shorts are $12
good luck,
ali

Answer 2

The shorts are $12 a piece and the tops are $6 a piece. 5x$12=$60 and 8x$6=$48 so $60+$48=$108

Answer 3

Call the shorts price y
Call the tops price z

then 5y + 8z =108 so the problem also says that

2z=y

so: five times two z plus 8z is 108

from there you can go to 10z + 8z + 108

so if 18z is 108 then z is 6

but z is the price of the tops

so go back to the problem and find out that the shorts cost twice as much as the tops

Do I have to tell you what two times six is?

Answer 4

let the price of top be x,then the price of a pair of shortsis 2x,thenthe cost of 5 pairs of shorts and 8tops is:
5*2x+8*x=108
18x=108
x=6
price of top =$6 and price of shorts=@12. AN.S.

Answer 5

We have the following 2 equations:

S = 2T.
5S + 8T = 108.

Since S = 2T, we can say:
5(2T) + 8T = 108.
10T + 8T = 108.
18T = 108.
T = 6.

And as a result, S = 2*6 = 12.

So the shorts were $12 per pair and the tops were $6 each.

Answer 6

Easy put it in a formula
2(5x)+8x=108

10x+8x=108

18x=108

x=6

so a top would be $6 and a pair of shorts is $12

Answer 7

Let price of shorts be $s and tops be $t
5s + 8t = 108
5 (2t) + 8t = 108
18t = 108
t = 6
s = 12
Tops cost $6
Shorts cost $12

Answer 8

5(2x)+8x=108
18x=108
x=6

shorts=2x or $12
top=x or $6