-1/3|2x+7|=2
its a abolsute value question help!
2007-09-10 07:40:27 · 5 answers · asked by Kwan L 2 in Science & Mathematics ➔ Mathematics
so we have:
-1/3|2x+7|=2
|2x+7| = -6
so first x>-7/2
2x+7=-6 ------> x = -13/2 (can't be taken as solution due to the condition above)
then x<-7/2
-2x-7=-6
2x+7=6
x=-1/2 --------> (can't be taken as solution due to the condition above)
the equation presents no solutions
2007-09-10 07:51:49 · answer #1 · answered by Alessandro 3 · 0⤊ 0⤋
no solution: I 2x + 7 I > 0, and so -1/3 of this quantity is negative, which cannot = 2.
2007-09-10 14:47:04 · answer #2 · answered by John V 6 · 0⤊ 0⤋
you may separate it into two equations.
1) -1/3(2x+7)=2
2) 1/3(2x+7)=2
2007-09-10 14:58:59 · answer #3 · answered by shanghai beach 3 · 0⤊ 1⤋
-1/3|2x+7|=2
Multiply both sides by -3 getting:
|2x+7|=-21
But this is impossible because |x| >= 0. It cannot be negative.
2007-09-10 14:52:23 · answer #4 · answered by ironduke8159 7 · 0⤊ 1⤋
-1/3I2x+7I=2
-1/3(2x+7)=2
-2/3x-7/3=2
-2/3x=2+7/3
-2/3x=6/3+7/3
-2/3x=13/3
-2x=13
x=-6 1/2
2007-09-10 14:50:47 · answer #5 · answered by Xiomy 6 · 0⤊ 0⤋