So I'm normally pretty decent at these but I can't seem to get this one, I think it's because the denominators are equal but anywho, can anyone help me out with this question:
[Intg from 5 to 12] (9x)/(x^(2)+4x+4)
Determine the numerical values of the coefficients, A and B, where B is less than or equal to A in
A/denominator + B/denominator
A=? B=?
I broke it up into A/x+2 and B/x+2 But that gives the equation of 9x=A(x+2)B(x+2) so I don't really know where to go from here...Do I have to do anything with the 5 and 12? Eeek, help! Thanks y'all!
2007-09-10 05:47:34 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Yes thanks! I got it =)
2007-09-10 06:09:52 · update #1
you have to brake it up into
A/(x+2)+B/(x+2)^2=
(A(x+2)+B)/(x+2)^2
Can you continue from here?
2007-09-10 05:56:32 · answer #1 · answered by Theta40 7 · 0⤊ 0⤋
You must use A/(x+2) +B/(x+2)^2
Clearing fractions gives:
A(x+2) + B = 9x
Set x = -2 getting B= -18
So A(-18+2) -18 =9
-16A = 27
A= -27/16
2007-09-10 13:12:34 · answer #2 · answered by ironduke8159 7 · 0⤊ 0⤋