Pythagorean Theorem?

Question

Using the Pythagorean Theorem calculate the value of x it the side measure b=^2 and c=25^2
a) 7
b) 13
c) 12
d) 4

b=24^2

and

c+25^2

Answer 1

x^2 + b^2 = c^2
==> plug in numbers
x^2 + 24^2 = 25^2
==> simplify
x^2 + 576 = 625
==> subtract 576 from both sides
x^2 = 49
==> square root both sides
x = 7 ... So your answer is (a).

Answer 2

Well, everybody seems to have answered your question...

But there's a shortcut...
There are 5 Pythagorean Triples... Right triangles with sides of integer lengths.... with at least one side less than 10.
3-4-5 is the most common
5-11-12 is the next most common.
7-24-25 I've seen this a couple times
8-15-17
9-40-41 I've only seen this one once.

Often they do multiples to hide the Pythagorean Triple such as 24-45-51

Answer 3

x² = a²

pythagorean Therom

c² = a² + b²

Transpose b²

c² - b² = a². . .←. .use this formula

√(25)² - (24)² = √a²

√625 - 576 = √a²

√49 = √a²

7 = a

Answer 4

a^2 + b^2 = c^2

Plug in the known numbers and solve for the unknown.

A^2 + (24^2) = 25^2
A^2 = (25^2) - (24^2)

Then you need to find the square root of the number to solve for A. That will be the missing side of your triangle.

Answer 5

a^2 + b^2 = c^2
a^2 + 24^2 = 25^2
a^2 + 576 = 625
a^2 = 49
a = 7

Answer 6

25^2 = 625
24^2 = 576

625-576 = 49

sqrt(49) = 7

Answer 7

x^2 + b^2 = c^2
or, x^2 + 24^2 = 25^2
or, x^2 + 576 = 625
or, x^2 = 49
or, x = 7 ... So your answer is (a).

Answer 8

pythagorean theorem applies only for right angled triangle....and if your triagle is right angle one...then the third side should be 7 units....

Answer 9

a

Answer 10

You really should do your own homework 8^).
http://en.wikipedia.org/wiki/Pythagorean_theorem