2007-09-10 04:50:27 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
To be an equation , RHS = 0
3x² + 5x + 9 = 0
[ - 5 ± √(25 - 108) ] / 6
[ - 5 ± √(- 83) ] / 6
[ - 5 ± i √(83) ] / 6
2007-09-13 19:44:09 · answer #1 · answered by Como 7 · 0⤊ 0⤋
How do you solve this equation.
CAN'T it's not an equation.
3X^2+5X+9 divided by X+1
= 3x + 2 Remainder 7
2007-09-10 12:40:05 · answer #2 · answered by harry m 6 · 0⤊ 0⤋
Assuming the RHS=0 then we multiply throughout by X to remove the X^-1 then we have
3X^3 +5X^2 +X +9=0
I'll leave it to you to simply apply the formula for solving for X found at
http://en.wikipedia.org/wiki/Cubic_function
2007-09-10 16:00:53 · answer #3 · answered by marcus101 2 · 0⤊ 0⤋
Multiply through by X
3x^3 + 5x^2 +x +9
This cubic does not factor. You need to use a calculator like a TI-89 to find the roots. There are three (of course).
-2.15695 , 0.245142 - i*1.153584 , 0.245142 + i*1.153584
2007-09-10 12:16:36 · answer #4 · answered by PMP 5 · 0⤊ 0⤋