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14 + 10x squared = 7y squared ...Please explain why or why not this is a function..and how you came up with the answer..thanks.

2007-09-10 03:51:03 · 5 answers · asked by ALF 2 in Science & Mathematics Mathematics

5 answers

Hey,

No, this is not a function. Let me explain why: if we were to solve for y alone, we would first divide by 7 and then take the square root of y. Once we take the square root of y, we now need to make sure that the other side of the equation says: +/- the square root.

Notice that this leads us with one vale of x gives us 2 values of y. A function would only have one x value give us 1 y-value.

Therefore, this isn't a function!

I hope that helps you out! Please let me know if you have any other questions!

Sincerely,

Andrew

2007-09-10 03:57:23 · answer #1 · answered by Anonymous 4 · 0 0

14 + 10x^2 = 7y ^2
y^2 = 2 + 10x^2/7
y = +/- sqrt(2+10x^2/7)
You should note that for any unique value of x there will be two values of y (one negative and one positive). Thus it is not a function. To be a function, there must be only one value of y for each value of x.

2007-09-10 04:04:09 · answer #2 · answered by ironduke8159 7 · 0 0

This is an equation where for given values of x and y the equation will hold true. A function is of the form y=f(x), where the value y is solely dependant on the single variable x when input into the function f, i.e. for every value of x there is one and only one corresponding value of y and the relationship can be plotted on a graph. Additionally, an expression of the form y=f(x,w,z..) is called a formula where the value of y is dependant on a number of independant variables.

2007-09-10 04:02:22 · answer #3 · answered by saiello2061 4 · 0 0

This is not a function because for each x value, you have two y values.
y = ±√[(14+10x^2)/7]

2007-09-10 03:56:45 · answer #4 · answered by sahsjing 7 · 1 0

No. It is an equation. A fuction may be expressed in f(x) or f as a quantity of x

2007-09-10 03:57:01 · answer #5 · answered by joseph 2 · 0 1

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