Determine the slope and the y intercept of the graph of the equation?

Question

1) x+y=-8
2) 2x-4y=8
your answers are very helpful I can not figure these out on a graph.

Answer 1

y = mx + b
is the general equation for a line

m = slope, b = y intercept

1) x+y=-8

y = -x - 8

-1 = slope, -8 = y intercept

2) 2x-4y=8

4y = 2x - 8

y = (1/2)x - 2

1/2 = slope

-2 = y intercept
.

Answer 2

Slope-intercept form: y = mx + b, where m is the slope and b is the y-intercept -x + 10y = 40 (add x to both sides) 10y = x + 40 (divide both sides by 10) y = (1/10)x + 4 And so the slope is 1/10 and the y-intercept is 4; point (0, 4).

Answer 3

The slope-intercept form of an equation is y=mx+c.So,y=-8-x here slope is -1 and y-intercept is -8.Similarly 4y=2x-8 & y=x/2-2.So slope is 1/2 & y.intercept is -2

Answer 4

You need to re-arrange the equations so they look like:
y = mx+b where m and b are the slope and y intercept.

For the first, x+y=-8, you need to get the "y" by itself on the left. Subtracting x from both sides does this:
y = -8 - x
TO make it look more like mx+b,
make it y = -x -8, or
y = -1*x + -8 where the slope is now clearly -1 and the y intercept -8.

I'll let you work on the second, but here is the basic way to do it:
SUBTRACT 2x from both sides
DIVIDE both sides by -4

Answer 5

to find y intercept: set x=0 and solve--

x+y= -8
0+y= -8
y= -8

then to find the slope put it into y= mx+b form by subtracting x from each side:

x+y -x = -8 -x
y= -x -8
Therefore the slope (m) is -1

Now just apply this method to number 2

Answer 6

for y-ints let x=0
1. x+y=-8
0+y=-8
y-int=-8

slope=gradient=coefficient of x, when in form y=mx+c, or y=ax+b

x+y=-8
y=-x-8
gradient=-1

2: for y-int, x=0
2(0)-4y=8
y=8/-4
y-int=-2

arrange into y=mx+c
2x-4y=8
2x-8=4y
y=2/4 x-8/4
y=1/2x-2
gradient=1/2

Answer 7

in order to find out the y intercept you have to make x=0