Hello folks!
How can i solve this quadratic equation using the QUADRATIC FORMULA?
5x^2+13x -6=0
I tried doing it but i got stuck on the way....
2007-09-09 23:40:56 · 9 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
thanks....
2007-09-09 23:41:10 · update #1
Please use the quadratic formula.
2007-09-09 23:51:44 · update #2
To Arundhati Bakshi,CPUcate and those who used the formula... thank you very much for your help. A lot of people dont seem to read my question very carefully.
2007-09-09 23:56:46 · update #3
x = [ -13 ± √(169 + 120) ] / 10
x = [ -13 ± √(289) ] / 10
x = [ -13 ± 17 ] / 10
x = 4 / 10 , - 30 / 10
x = 2 / 5 , x = - 3
2007-09-10 07:37:04 · answer #1 · answered by Como 7 · 1⤊ 0⤋
x = (-b+-sqrt(b^2-4ac))/2a
a = 5, b = 13, c = -6
x = (-13+-sqrt(13^2-4(5)(-6)))/2(5)
x=(-13+-sqrt(169+120))/10)
x=(-13+-sqrt(289))/10)
x= (-13+-17)/10
x = (-13-17)/10 or x = (-13+17)/10
x = -30/10=-3 or x = 4/10=2/5
2007-09-09 23:52:01 · answer #2 · answered by Runa 7 · 1⤊ 0⤋
x = [ -13 +- sqr(13^2 + 4(5)(6) ] / 10
x = [ -13 +- sqr(289 ] / 10
x = [ -13 +- 17] / 10
x1 = [ -13 + 17]/10 = 4/10 = 2/5
x2 = [ -13 - 17]/10 = -30/10 = -3
2007-09-09 23:53:41 · answer #3 · answered by CPUcate 6 · 1⤊ 1⤋
5x^2+13x -6=0
5x^2+15x-2x-6=0
5x(x+3)-2(x+3)=0
(5x-2)(x+3)=0
so x= -3 or X=2/5
2007-09-09 23:51:01 · answer #4 · answered by Mr Myth 3 · 1⤊ 1⤋
x = (-b+-sqrt(b^2-4ac))/2a
a = 5, b = 13, c = -6
x = (-13+-sqrt(13^2-4(5)(-6)))/2(5...
x=(-13+-sqrt(169+120))/10)
x=(-13+-sqrt(289))/10)
x= (-13+-17)/10
x = (-13-17)/10 or x = (-13+17)/10
x = -30/10=-3 or x = 4/10=2/5
2007-09-10 00:06:04 · answer #5 · answered by Anonymous · 1⤊ 1⤋
ur equation is 5x^2+13x-6=0
u can break the middle term as 5x^2+15x-2x-6=0
5x(x+3)-2(x+3)=0
(5x-2)(x+3)=0
x=2/5, -3
2007-09-09 23:52:19 · answer #6 · answered by Gaurav A 1 · 1⤊ 1⤋
The answer is...
(5x - 2)(x + 3) = 0
So...
5x = 2 or x = -3
x = 0.4 or -3
2007-09-09 23:48:15 · answer #7 · answered by Lisa 2 · 1⤊ 1⤋
standard form of a quadratic
y = ax^2 + bx + c
Quadratic Formula
-b plus or minus Square root of(b^2 - 4ac)
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x = 2a
if you follow the formula you get:
[(-13) plus or minus 17
__________________
10
finally you get
.4 or -3
2007-09-10 00:03:01 · answer #8 · answered by James H 3 · 1⤊ 1⤋
5x^2+15x-2x-6
5x(x+3)-2(x+3)
(5x-2)(x+3)
2007-09-09 23:50:33 · answer #9 · answered by **PiNoY YFC** 7 · 1⤊ 1⤋