1)2*3,4*6,6*9,8*12,...
2)1/3,2/5,3/7,4/9,....
2007-09-09 18:06:34 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
1. a_n = (n+1)(3n) where n = 1,2,3...
This isn't an arithmetic sequence.
2. a_n = n/(2n+1) where n = 1,2,3...
This isn't an arithmetic sequence either.
2007-09-09 18:17:38 · answer #1 · answered by Demiurge42 7 · 0⤊ 0⤋
enable's take f(2) = 4 +5/7 -6 = -9/7 f(3) = 6 +5/7 -9 = -sixteen/7 f(4) = 8 +5/7 - 12= -23/7 discover the version between -sixteen/7 and -9/7 -sixteen/7 - (-9/7) = -sixteen/7 + 9/7 = -a million discover the version between -23/7 and -sixteen/7 -23/7 -(-sixteen/7)= -a million So the transformations interior the words are consistent. primary equation: an = a +(n-a million)d = -2/7 - (n-a million) = -2/7 -n +a million = 5/7 - n i'm no longer so particular whether it does fulfill the circumstances of an arithmetic series: the version between the words different than for the 1st are consistent. d = -a million You upload -a million to get from one term to the subsequent.
2016-10-18 12:25:02 · answer #2 · answered by Anonymous · 0⤊ 0⤋