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There is some confusion in terminolgy here, probably on my part. Ray, you`re correct about 2mc being the1st dir of e=mc^2: But, that wasn`t my question.
I want to know what the funtion is (integral?) if mc^2 is the 1st dirivity of the funtion I`m looking for!

2007-09-09 16:39:34 · 5 answers · asked by Anonymous in Science & Mathematics Mathematics

5 answers

I'm a bit confused. Not just because I'm unsure of what you want to integrate with respect to, but moreso what is the answer you are looking for, is there any reason you are asking this question, are you looking for information as to finding e=mc^2? There could be many answers to your question, depending on the original function you are looking for. Can you please be more specific with you question?

2007-09-09 17:42:42 · answer #1 · answered by Anonymous · 0 0

If its anti differivative than the integral of e=mc^2 would probably be: e=[(mc^3)/3] + C... based on the reverse chain rule..

2007-09-12 04:45:58 · answer #2 · answered by Prince 4 · 0 1

i assume that c^2 is a constant so we are integrating with respect o m...

thus..
int (mc^2)*dm = (m^2/2)*(c^2) + C

2007-09-09 23:50:44 · answer #3 · answered by quigonjan 3 · 0 1

depends what we are integrating across.


e dx = mxc^2

===
Dont be arrogant to believe we dont know what we're talking about.

Specify a variable for integration and we will integrate it.

2007-09-09 23:46:33 · answer #4 · answered by Anonymous · 0 1

it would be 1/3mc^3

2007-09-09 23:45:01 · answer #5 · answered by neogeoloco@sbcglobal.net 2 · 0 2

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