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csc x=-2; x in QIV; cot x=?
tan x=3; x in QIII; sin x=?


I think i know the answer to the first one. The Tan would be -1/sqrt3 (you dont have to rationalize) so the cot would be -sqrt3/1 correct?
Thanks!

2007-09-09 16:29:04 · 2 answers · asked by Kevin D 2 in Science & Mathematics Mathematics

2 answers

Cosecant is reciprocal sine, so the angle would be -30 degrees. So the cotangent would indeed be -sqrt(3). Sketching the second problem, the hypotenuse is sqrt(10), and the vertical side is 3, so the sine is 3/sqrt(10).

2007-09-09 16:50:28 · answer #1 · answered by Anonymous · 0 0

- sqrt(3) [the cot is negative QIV]

sin x = -3/sqrt(10) = -.3sqrt(10) {sin - in QIII}

2007-09-09 16:51:37 · answer #2 · answered by ironduke8159 7 · 0 0

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