Find a polynomial function with integer coefficients that have the given zeros: (1+squareroot of 3i), 2, 2, (-1-squareroot of 2)
2007-09-09 16:11:55 · 6 answers · asked by kat 2 in Science & Mathematics ➔ Mathematics
It will be pretty hard to do. If you have one imaginary root, you have to have another.
2007-09-09 16:18:11 · answer #1 · answered by cattbarf 7 · 1⤊ 2⤋
(x-(1+squareroot of 3i)) multiply (x-2) multiply (X+2) multiply (x-(-1-squareroot of 2))
my good so easy ..... looks like you don't andestand what means the zero of a polynomial ....
a zero, is a value of x that makes the polynomial = 0
i guessed it is 2 and -2 ....
looks like i am to slow to answer ... there are already the good answer..
tanpis ! (sorry i don't know how to say that in english
)
salut ma poule
ok ..
humm i am sure there are grammar mistakes... so if you what to suggest me correction ..
thank from the foreign guy
2007-09-09 23:20:44 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Multiply up the following:
(x-(1+square root 3i))(x-2)(x-2)(x-(-1-square root 2))
To find the function, all you have to do is take (x minus the zero) of that given function.
2007-09-09 23:17:59 · answer #3 · answered by gamers71320 3 · 0⤊ 0⤋
Pawn your homework off on Y! answers... I give you a big PFFFFF
But sorry, I'm stupid to math unless you need to know how much a 12 oz cappuccino should weigh, or the temperatures at which butter will fuse itself into certain recipes
2007-09-09 23:17:14 · answer #4 · answered by scott g 3 · 0⤊ 0⤋
bleh
sorry cant help u there
but i no how ur feel
lolz ;)
2007-09-09 23:17:59 · answer #5 · answered by ♥ 3 · 0⤊ 0⤋
wow!
Sorry, I am not too sure!
2007-09-09 23:17:44 · answer #6 · answered by ~♥Lavendaluva♥~ 3 · 0⤊ 0⤋