(- 8) ^(1/3)
= ( 8 i ² )^(1/3)
= 2 x (-1)
= - 2
2007-09-10 05:11:33
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answer #1
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answered by Como 7
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You need to find the number so that that number times itself times itself again is equal to your answer. First of all -2 is the answer since -2 x -2 = 4 and 4 x -2 = -8 Another way to think about this is to take out the negative. The cube root of (xy) is the cube root of x time the cube root of y. So think of the 8 as (-1 x 8). The cube root of -1 is -1. The cube root of 8 is 2. The cube root of (-1 x 8) is (-1 x 2) = -2
2016-05-20 23:30:42
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answer #2
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answered by ? 3
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2*2*2=8 so the cubed root of 8 is 2. The cubed root of -8 would be -2, because
-2*-2=4, then 4*-2=-8. I hope I am remembering this right.
2007-09-09 15:51:32
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answer #3
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answered by crazylady 3
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-2 * -2 * -2 = -8
2^3 is the cube root of -8
2007-09-09 16:55:31
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answer #4
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answered by YinDenYang 3
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What you're trying to find is the number that when multiplied by itself 3 times would be -8.
3 x 3 x 3=27 wrong
2 x 2 x 2=8 wrong
-2 x -2 x -2= -8 right
2007-09-09 15:48:01
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answer #5
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answered by Anonymous
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the cube root of -8 is -2, since -2 x -2 x -2 = -8
2007-09-09 15:46:44
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answer #6
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answered by SNLfan52 3
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you memorize or factor
what are the prime facors of 8? of -8?
8=2*2*2 = 2^3
-8 = -2*-2*-2 = (-2)^3
cubed root of a^3 = a
cubed root of -8 = cubed root of (-2)^3 = -2
2007-09-09 15:50:24
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answer #7
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answered by trogwolf 3
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what number multiplied by itself three times equals -8
it is mostly a memorization thing or factor it
-8
4*-2
-2*-2*-2
so -2 is the cube root of -8
2007-09-09 15:47:40
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answer #8
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answered by jayphelps321 2
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find a number that, when multiplied by itself 3 times equals - 8
so, you know that it has to be a negative number, because the root is odd -- and the number is negative . . .
so, start small and work your way up.
-1 x -1 x -1 = -1
-2 x -2 x -2 = -8
yay! we got the answer!
2007-09-09 15:47:30
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answer #9
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answered by Anonymous
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as it is cubed, you do not have an irrational answer, the answer will be -2, -2x-2 is 4, 4x-2 is -8.
2007-09-09 15:48:05
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answer #10
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answered by Anonymous
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