The greater of 2 consecutive even integers is six less than twice the smaller.?

Answer 1

x - greater
y - smaller

x - y = 2
x = 2y - 6 so x - 2y = -6

subtract 2nd eq from 1st

y = 8 and x = 10

Answer 2

n is the smaller integer, n + 2 is the greater
(n + 2) = 2n -6
8 = n
n + 2 = 10

verify:
10 = 2(8) - 6
10 = 16 - 6
10 = 10

Answer 3

let say
x = is the smaller number
x + 2 = the greater number
2x = (x+2) - 6
2x = x + 2 - 6
x = -4 is smaller number and (x + 2) = -2 the greater number
the greater number is six less than = -2-6 = -8
twice the small number = -4x2 = -8

Answer 4

x is smaller, x+2 is greater
2x-6 = x+2
x = 8
smaller integer is 8
greater integer is 10

Answer 5

given:
let:
ist integer = x
2nd integer = x + 2
substituting in the equation:
x + 2 = 2x - 6
transposing:
2x - x = 2 + 6
x = 8
x + 2 = 10
answers are 8, 10

hope this helps!