2007-09-09 15:06:21 · 7 answers · asked by jman146 2 in Science & Mathematics ➔ Mathematics
1) rearrange the equation into the y=mx+b form.
2) y=-3x/5+11/5. Slope is -3/5
3) To be perpendicular, the other equation must have a slope of +5/3. Lines are perpendicular when the slopes are reciprocals and one is positive and the other negative.
2007-09-09 15:14:50 · answer #1 · answered by Ed S 4 · 0⤊ 0⤋
Well........ It really isn't 'the' line since there will be an infinite number of lines perpendicular to any given line. But the slope of a perpendicular line is -1/m where m is the slope of the given line. In your case 3x + 5y = 11 can be re-written as
y = (-3/5)x +(11/5)
so any line that is perpendicular to it will have a slope of 5/3 and can be written as
y = (5/3)x + b
where the b is a constant (called the 'y intercept'). To find the b, you hae to know the (x, y) coordinates of a point the perpendicular line passes through. Then just plug them in for the x and y values and solve the equation for b.
HTH
Doug
2007-09-09 22:21:54 · answer #2 · answered by doug_donaghue 7 · 0⤊ 0⤋
The perpendicular line will have a slope that is the opposite reciprocal of that line. Rearrange 3x + 5y = 11 so it's in point-slope form (y=mx+b)
5y = -3x (disregard 11 since we just need the slope)
y = -3/5 x
The slope is -3/5.The perpendicular line will have a slope of 5/3.
So it would be y = 5/3x + b. What b is depends on whether it has to pass through a certain point.
2007-09-09 22:16:57 · answer #3 · answered by asdf 3 · 0⤊ 0⤋
Ignore him, the internet is a great way to learn how to do these things, I used it countless times in calc and pre calc. However, I'll warn you that I've never been good at finding perpendicular lines. If I'm right, you first want to get the 5y by itself, so subtract 3x from each side, leaving 5y=11-3x. Then since you know you need y, divide each side by 5, leaving y=(11/5)-((-3/5)x). Since the slope is now -3/5, you need the opposite reciprocal of the slope, which would be 5/3. So if I'm right, it's y=5/3X. However PLZ PLZ PLZ PLZ PLZ PLZ PLZ check that with someone else before handing that in, I'd hate to be responsible for getting that wrong for you.
2007-09-09 22:18:25 · answer #4 · answered by Anonymous · 0⤊ 0⤋
First you must put the equation into slope intercept form (y=mx+b).
3x+5y=11
Subtract 3x over to other side. 5y= -3x+11
Next divide by 5 to both sides. y= -3/5x+11/5
Now to get it perpendicular you must find the "opposite reciprocal" of the slope which is 5/3x.
The answer would be y=5/3x+11/5
2007-09-09 22:21:37 · answer #5 · answered by Anonymous · 0⤊ 0⤋
y = 5/3x + 11/5
2007-09-09 22:13:39 · answer #6 · answered by j p 2 · 0⤊ 0⤋
Self-reliance is the key. Learn this now.
2007-09-09 22:11:26 · answer #7 · answered by Anonymous · 0⤊ 1⤋