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Can someone show me how to do this.
Factor by grouping
x^5+4x^3-2x^2-8
thanks so much

2007-09-09 15:05:13 · 2 answers · asked by dtrain2419 1 in Science & Mathematics Mathematics

2 answers

x^5+4x^3-2x^2-8
=x^3(x^2 +4) -2(x^2+4)
=(x^3-2)(x^2+4)

2007-09-09 15:09:50 · answer #1 · answered by ironduke8159 7 · 0 0

x^5+4x^3-2x^2-8 =
(x^5 -2x^2) + (4x^3 -8) =
x^2 · (x^3-2) + 4· (x^3-2) =
(x^2+4) · (x^3-2)

Saludos.

2007-09-09 22:10:16 · answer #2 · answered by lou h 7 · 0 0

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