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how do u integrate sec^5xtanx

2007-09-09 14:24:08 · 2 answers · asked by crazed1511 1 in Science & Mathematics Mathematics

2 answers

u= secx
du=secxtanx

Int(sec^5xtanx)dx
=Int(sec^4xsecxtanx)dx
=Int(u^4)du
= u^5/5 + c
= sec^5x/5 + c

2007-09-09 14:32:09 · answer #1 · answered by Anonymous · 0 0

Integrate (sec^5x)(tanx) with respect to x.

∫(sec^5x)(tanx) dx

= ∫(sec^4x)(secx)(tanx) dx
Let
u = secx
du = (secx)(tanx) dx

= ∫(u^4)du

= (1/5)u^5 + C

= (1/5)(sec^5 x) + C

2007-09-09 14:34:22 · answer #2 · answered by Northstar 7 · 1 0

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