Math Problem?

Question

Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling at 100 mph and Train B is traveling at 104 mph. Train A passes a station at 2:20 pm . If train B passes the same station at 2:50 pm at what time will Train B catch up to Train A.

Answer 1

The relative speed of the two trains is (104-100)=4 mph
as the speed of train A is 100 mph.by the time train B reaches the station at 2-50pm,the train A has already travelled 1/2*100 or 50 miles
Hence when the train Breaches the station.train A is 50 miles ahead of it.
Their relative speed being 4 mph,train B requires (50/4) or 12.5 hrs or 12 hrs 30 minutes to catch up with train A
Therefore train B will catch up train A at
2-50 pm+12 hrs 30 minutes
=3-20 am next day

Answer 2

At 2:50 train A has travelled 50 miles past station and train B is at station.
Relative speed of B to A = 4 mph
t = 50 / 4 hours
t = 12.5 hours
t = 12 hours 30 minutes
Will catch up at 14:50 + 12:30 = 27:20 = 03:20

Answer 3

Train A has a 30 minute head start on train B. 100 mph multiplied by half an hour is 50 miles so train A has a 50 mile lead. Train B travels 4 mph faster so it will take it 50 miles/4mph or 12½ hours to catch up.

Answer 4

X = amount of time Train B will catch up with Train A

Train A = 100 mph/X-0.5(ahead half hour)
Train B =104 mph/x
100/x-0.50 =104/x
104x-52=100x
4x=52
x=13 hours Train B will cath up with Train A or 3:50 AM the next day that Train B catch up with Train A, assuming both of them keep traveling at the same speed as given.

Answer 5

Train B is 0.5 hr behind A at the station, so A has 50 miles less to travel by that time. B has to travel X mi and A has to travel X - 50 mi, so X/104 = (X-50)/100.

100X = 104(X - 50) = 104X - 5200
4X = 5200
X = 1300 mi for train B
Train B travels 1300 mi in 1300/104 = 12.5 hr, so the time will be 3:20 AM.

Answer 6

When train B passes the station, train A is what distance past the station? Half an hour at 100 miles per hour.

The distance between B and A diminishes at a rate of 104 - 100 miles per hour. Take the distance between the train at "time zero" when B passes the station and divide it by the rate at which it diminishes.

D = distance between B and A, calculated above at 2:50 pm.
T = D / (104 - 100) mi. per hour

T will be the time required, in hours.

Answer 7

Ok so Train B is 30 minutes behind Train A.

At that point, Train A is 50 miles ahead of Train B (100mph) for a haf hour (30 min)

Train B is gaining 4mph on Train A.

So, 50 miles divided by 4 miles per hour is....

12 hours 30 minutes :)

Answer 8

first, let's how far behind car A is car B is at 2:50 pm

from 2:20pm to 2:50pm is .5hr

d = (100)(.5)
d = 50 miles

so at 2:50pm car B is 50 miles bind car A

let t be the time since 2:50pm

distance of car A
d = 100t

distance of car B
d = 104t - 50

when car B catches car A, they are in a same postion
100t = 104t - 50
4t = 50
t = 12.5 hrs

it will take car B 12.5 hrs to catch car A or at 3:20 am

Answer 9

Never. Train A is always faster and thus will continue to increase the distance beteen them.

Answer 10

never its a trick question good luck