Factoring!?

Question

Does anybody know how to factor any of these problems?

5a^2+9a-2

25u^2-20u+4

6u^2+17u-10

And how do you solve them?

Answer 1

(5a-1)(a-2)

(5u-2)(5u-2)

(3u + 10)(2u - 1)

You multiply a and c and find their factors
if the product is position you add the two factors until it is eq b
if the product is negative you subtract

eq. 5 x 2 = 10 and 1 and 10 is factor of 10 and 10 - 1 = 9
6 x 10 = 60 and 3 and 20 is factor of 60 and 20 - 3 = 17

Answer 2

5 a^2 + 9a - 2 = (5a -1)(a + 2),,

25 u^2 - 20u + 4 = (5u - 2)^2,,

6u^2 + 17u - 10 = (3u + 10)(2u -1),,

First, get the factors of the first and last expressions.
Then choose which of the factors will give the middle expression.
The sign of the expressions greatly affect the sign of the answer factor.
If all the given expression is positive the factor will have the format (a+b)^2.
if it is x -y +z then the format is (a-b)^2.
if it is x (- or +) y -z then the format will be (a-b)(c-d)
where a and c, or b and d can be equal depending on the equation.

Answer 3

5a^2 +9a-2 = (a+2)(5a-1)
25u^2 -20u+4 = (5u-2)(5u-2)
6U^2+17u-10=(6u-5)(u-2) the equation must have a positve sign or should be: 6u^2 -17+10 not the one you have submitted!

Answer 4

5a^2+9a-2
(1a+2)(5a-1)

the number 5 is only dividable by 5 and 1 so that is easy, the hard part is finding the other numbers, -2 is only dividable by 2 and 1, then you play until you get the right formula....

Answer 5

5a^2+9a-2 = 5a^2+10a-a-2 = 5a(a+2) - (a+2)
=(5a -1)(a + 2)

Answer 6

5a^2+9a-2
=5a^2+10a-a-2
=5a(a+2)-1(a+2)
=(a+2)(5a-1)
25u^2-20u+4
=(5u)^2-2*5u*2+(2)^2
=(5u-2)^2
6u^2+17u-10
=6u^2+20u-3u-10
=2u(3u+10)-1(3u+10)
=(3u+10)(2u-1)