geometry question?

Question

the sides of a rectangle are in the ratio 3:2. what is the length of each side if the perimeter of the rectangle is 55cm?

steve if u could help me gain that'd be great thnks!

Answer 1

Let
2x = width of rectangle
3x = length of rectangle

Then we have:

2(2x) + 2(3x) = 55
4x + 6x = 55
10x = 55
x = 5.5

2x = 2*5.5 = 11
3x = 3*5.5 = 16.5

Width = 11 cm
Length = 16.5 cm

Answer 2

A ratio of 3:2 means that if two sides were 3cm then the other 2 would be 2cm. This would give a perimiter of 10cm.

55 (the perimiter) divided by 10 (the perimiter if using the basic ratio) = 5.5

so 1:1 = 5.5 x 5.5 x 5.5 x 5.5

3:2 = (5.5 x 3) + (5.5 x 2) which is 16.5 and 11 these are the lengths as 16.5 x 2 and 11 x 2 = 55cm

Answer 3

Let the sides of the rectangle be 3x and 2x respectively
we know that the perimeter of a rectangle is 2(length +width)
Therefore,according to the problem.
2(3x+2x)=55
or2*5x=55
or 10x=55
orx=55/10=5.5
Therefore,
The length of the rectangle=3*5.5=16.5 cm
and the width =2*5.5=11 cm

Answer 4

let l=length w=width
l/w=3/2
2l=3w
l=3w/2
P=2(l+w)=55
2(3w/2+w)=55
2(5w/2)=55
5w=55
w=11 cm
l=3(11)/2=16.5 cm

Answer 5

Let 3x & 2x represent the sides.
Then: 2(3x + 2x) = 55
10x = 55, x = 5.5,
Substituting, the sides are:
3(5.5) & 2(5.5),
16.5 & 11

Answer 6

l/w = 3/2 --> l = 3w/2
So perimeter = 2(w+3w/2) = 5w
5w = 55 so w = 11
l = 3*11/2 = 16.5

Answer 7

Use a algebraic equation.
2(3x)+2(2x)=55
6x+4x=55
10x=55
x=5.5 (now plug it back in)

3(5.5)=16.5
2(5.5)=11

Answer 8

6x+4x=55
10x=55
x=5.5
11 by 16.5