Help me calculate this function?

Question

Given the function f(x)=5 |x-1|, calculate the following values:

f(x+1)
f(x^2+s

Note: Just to clarify, the x-1 is in between absolute value signs

Answer 1

f(x+1) = 5|(x+1) - 1| = 5|x|
f(x² + s) = 5|(x²+s) - 1| = 5|x²+s-1|