2007-09-09 12:59:44 · 7 answers · asked by rupi s 2 in Science & Mathematics ➔ Mathematics
3x + 5 = n+ xy
3x - xy = n - 5
x(3 - y) = n - 5
x = (n - 5)/(3 - y)
2007-09-09 13:05:26 · answer #1 · answered by Tom :: Athier than Thou 6 · 0⤊ 0⤋
3x+5 = n+xy
3x-xy =n-5
(3-y)x=n-5
x = (n-5)/(3-y)
2007-09-09 20:11:31 · answer #2 · answered by Skrap 3 · 0⤊ 0⤋
3x + 5 = n + xy
3x - xy = n -5
x(3-y) = n-5
x = (n-5)/(3-y)
2007-09-09 20:06:36 · answer #3 · answered by Will 4 · 0⤊ 0⤋
3x + 5 = n + xy
3x - xy = n - 5
x (3 - y) = n - 5
x = (n-5) / (3-y)
2007-09-09 20:05:47 · answer #4 · answered by Anonymous · 0⤊ 0⤋
3x + 5 = n + xy
3x - xy = n - 5
x (3 - y) = n - 5
x = (n - 5) / (3 - y) ,,
2007-09-09 20:07:43 · answer #5 · answered by ARCangel 1 · 0⤊ 0⤋
3x+5=n+xy
3x = n + xy - 5
3x -xy = n - 5
x(3-y) = n - 5
x = (n - 5)/(3 - y)
2007-09-09 20:04:02 · answer #6 · answered by bedbye 6 · 0⤊ 1⤋
ummm.....42??...sorry cant help you here way too hard for my 8th grade skills!
2007-09-09 20:06:45 · answer #7 · answered by Anonymous · 0⤊ 0⤋