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f(x)= x-1 / x^2- 4

how do you find domain?

2007-09-09 12:31:45 · 4 answers · asked by snowangels 2 in Science & Mathematics Mathematics

4 answers

You can't have 0 on the bottom of a fraction, so x squared - 4 can't be 0.
That means x squared can't be 4
That means x can't be 2 or -2, but it can be anything else.

2007-09-09 12:36:11 · answer #1 · answered by ccw 4 · 0 0

In a quotient, it's usually the roots of the denominator that control the domain set. In this case, the domain would be the set of all reals --except-- +2 and -2 (since at those values, x²-4 = 0)

HTH

Doug

2007-09-09 12:40:34 · answer #2 · answered by doug_donaghue 7 · 0 0

Sorry, but if the denominator had a square root the domian would be [-2,2], but since it doesn't I don't think this problems domain can't be found.

2007-09-09 12:37:12 · answer #3 · answered by Cherry 2 · 0 0

Next time use parenthesis

I understand this: x - (1/x^2) - 4 but you probably ment this:

(x-1)/(x^2 -4)

Ana

2007-09-10 08:58:20 · answer #4 · answered by MathTutor 6 · 0 0

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