Each side of a square is lengthened by 3 inches. The area of this new, larger square is 64 square inches. Find the length of a side of the original square. (please show work)
2007-09-09 11:34:02 · 9 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
x = side of original square
(x+3)² = 64
x+3=8
x=5
2007-09-09 11:38:37 · answer #1 · answered by chasrmck 6 · 2⤊ 0⤋
The new square is 64 sq in, so the length of its sides must be
â64 = 8 inches.
Now subtract 3 inches from 8 inches and get 5 inches as the length of the original square.
Doug
2007-09-09 18:42:36 · answer #2 · answered by doug_donaghue 7 · 0⤊ 0⤋
let s = side of the original square
...each side of a square is lengthened by 3 inches...
new length = s+3
...The area of this new, larger square is 64 square inches....
new area = (s+3)^2 = 64
s+3 = 8
s = 8-3
s = 5
2007-09-13 08:31:47 · answer #3 · answered by Pakyuol 7 · 0⤊ 0⤋
sqrt(64) = 8 is the side of the new square
the sides are increased by 3, so 8 - 3 = 5 is the side of the original square
answer: 5in
2007-09-09 18:44:32 · answer #4 · answered by 7 · 0⤊ 0⤋
(s+3)^2 = 64
s^2 + 6s + 9 = 64
s^2 + 6s - 55 = 0
(s+11)(s-5) = 0
s = 5 . . . . . . original side of square
2007-09-09 18:41:29 · answer #5 · answered by CPUcate 6 · 0⤊ 0⤋
s = the new side length
s^2 = 64 square inches
s = 8 inches
s - 3 = original side length
Ans. 5
2007-09-09 18:38:54 · answer #6 · answered by cjcourt 4 · 0⤊ 1⤋
5 inches
2007-09-09 18:52:17 · answer #7 · answered by 222 3 · 0⤊ 0⤋
squre root of 64 is 8
8-3 =
5
not that hard.
2007-09-09 18:39:10 · answer #8 · answered by Like Woah 3 · 0⤊ 0⤋
(x+3)^2=64
(x+3)^2=(8)^2
x+3=8
x=8-3
x=5
2007-09-09 18:41:41 · answer #9 · answered by kerga 2 · 0⤊ 0⤋