solve the problem by writing an inequality?

Question

Find the lesser of 2 consecutive integers with a sum greater than 16

Answer 1

x= 1st
x+1 = 2nd

x+x+1>16
2x>15
x>7.5

so x = 8

Answer 2

a million.) He can't spend greater desirable than 30 funds, so the equation ought to end in < 30. Use the style of pizzas he ought to purchase as x and multiply that via 7.ninety 9, and then upload yet another 2. So the inequality is: 7.99x + 2 < 30 Subtract 2 from the two factors: 7.99x < 28 Divide the two factors via 7.ninety 9 (rounded to eight): x < 3.5, which whilst rounded down is 3. So Allen ought to purchase 3 pizzas. 2.) Translate each and every area: "whilst a huge decision is better via -2": -2x "effect is a minimum of 18": > 18 Inequality: -2x > 18 to resolve for the inequality, divide the two factors via 2. yet, considering the fact which you're dividing via a unfavourable, make specific to alter the sign! meaning you get x < 9. So the main that x could properly be is 8.

Answer 3

let the integers: x, x+1
X+(X+1)>16
2X>15
X>15\2
X>7.5

then the lesser of 2 consecutive integers are 8 and 9..

Answer 4

9+8=17
So the lesser would be 8.

Answer 5

lowest has to be 8+9, and if you call the smallest one x, the inequality would be
x>8

have yourself a good day.