What is the derivative of j(x)=asinb(x+c)?

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2007-09-09 08:45:32 · 2 answers · asked by ? 1 in Science & Mathematics ➔ Mathematics

j (x) = a sin (bx + bc)
j `(x) = a b cos (bx + bc)
j `(x) = a b cos [ (b) (x + c) ]

2007-09-12 07:12:57 · answer #1 · answered by Como 7 · 1⤊ 0⤋

Assuming that a, b, and c are constants then this is just the derivative of sin(x):

j'(x)=acos(bx+c)(b) (using the chain-rule)

2007-09-09 15:58:10 · answer #2 · answered by Anonymous · 0⤊ 1⤋