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The charge distribution is an open-ended cylindrical shell of charge q, radius R, and length H (a cylindrical side with no ends). The Gaussian surface S is a cylindrical shell with radius r and length h, with r > R. Determine the net electric flux given that q = 8Q, R = 5L, H = 4L, r does not apply, and h = 3L (type the integer value, along with the sign, without typing units Q/e0):


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2007-09-09 06:59:47 · 2 answers · asked by NOne N 1 in Science & Mathematics Physics

2 answers

Assume that the charge is uniformly distributed on the open-ended cylindrical shell. Also centering Gaussian shell length h on the open-ended cylindrical shell length H, such that the electric flux through both ends of the Gaussian shell is negligible (approaching the case when H is > > h). Since the total charge in the Gaussian shell is 8Q*(h/H) = 6Q, the TOTAL net electric flux is 6Q/e0.

2007-09-09 13:21:23 · answer #1 · answered by Hahaha 7 · 0 0

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2016-12-13 04:18:21 · answer #2 · answered by ? 4 · 0 0

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