find the derivative of y= 6/5x?

Answer 1

y = (6/5) x is assumed question.
dy/dx = 6/5
Brackets required in question to avoid confusion and incorrect answers.

Answer 2

It's 6/5.

y=6/5x is the same as y=(6/5)*x^1 therefore when you take the derivative it is y=1*(6/5)*x^0 and since x^0 is 1 it becomes y=1*(6/5)*1 which is y=6/5

Answer 3

d(6/5x)/(dx) = 6/5

You should have learned in class or from your book that the derivative of a function like such:
f(x) = x^n
then f'(x) = (n)x^(n-1).

Which is almost like the equation you were given, except you had a constant of 6/5.

f(x) = 6/5x^1
f'(x) = (6/5 * 1)x^(1-0) = 6/5x^0 = 6/5(1) = 6/5

Remember that anything raised to the "zero power" is simply 1.

Good luck!

I hope this helps you.

Love,
Mary

Answer 4

y' = 6/5

Answer 5

6/5 is a coefficient of 1/x. So now we can set the problem as this; y= (6/5)*(1/x). This can be rewritten as y=(6/5)*(x^-1). Following this guideline of F'(x)= N*x^(N-1) we can do this now.

y = (6/5)*(x^-1)
dy/dx = ((dy/dx)[(6/5)*(x^-1)])
dy/dx = ((-1)*(6/5))*(x^(-1-1))
dy/dx = (-6/5)*(1/x^2)
dy/dx = -6/5x^2 (assumming that it is 6/(5x) and not (6/5)x.)

Answer 6

all the above answers are correct if

6/5 x = 6x/5 is what you have
dy/dx = 6/5

BUT

if you are asking about 6/ (5x) then your derivative is:

y = 6/5 (x^-1)
dy/dx =(65)(-1)/(x²)

So which one is it?

Answer 7

6/5
in equations of this form you just take x's coefficient