2a(3-4a)=
6a-8a
and..
2x-(3+5x)
6x-10xsquared.
^^ I know I did that one wrong.
Did I do it right?
If I didn't tell me what to fix.
also I am extremely stuck on this one,-(3x+2y-1).
2007-09-09 06:22:46 · 5 answers · asked by Jenniefrizzzle 4 in Science & Mathematics ➔ Mathematics
Well, the first one you did correctly. But, you can definitely further simplify that I mean you should be able to do 6a - 8a (just exactly like 6-8).
The second one: 2x - (3 + 5x)
NOTICE THE NEGATIVE/MINUS SIGN
2x - 3 -5x
Now solve from there.
-(3x + 2y - 1)
Factor in the minus/negative sign first:
-3x - 2y +1. They're all different terms/variables so you shouldn't further simplify this. it's great as is.
GOOD LUCK!
Hope this helps.
Love,
Mary
2007-09-09 06:30:28 · answer #1 · answered by ♥ Mary ♥ 3 · 0⤊ 0⤋
2a(3-4a) = 6a -8a^2 you were incorrect with regards to the exponent in the second term
2x-(3 + 5x) = 2x -3 -5x = -3 -3x = -3(1+x)
6x-10 X^2 = 2x(3-5x)
-(3x + 2 y -1) = -3x -2y + 1
look over what I did and understand this. In the first one, you forgot the exponent; understand why
2007-09-09 06:29:34 · answer #2 · answered by GTB 7 · 0⤊ 0⤋
2a(3-4a) = 6a - 8a²
2x-(3+5x) = 2x-3-5x = -3x-3
-(3x+2y-1) = -3x-2y+1
2007-09-09 06:27:23 · answer #3 · answered by Anonymous · 1⤊ 0⤋
First is all right.
2x-(3+5x) = 2x-3-5x (just change sign in bracket and remove bracket)
-(3x+2y-1) = -3x-2y+1 ( simmilarly)
2007-09-09 06:28:23 · answer #4 · answered by Anonymous · 0⤊ 0⤋
2x-(3+5x) = -3x-3 trust me you distribute the negative
2007-09-09 06:27:33 · answer #5 · answered by Anonymous · 0⤊ 0⤋