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2007-09-09 06:21:40 · 4 answers · asked by Kamil n 1 in Science & Mathematics Chemistry

4 answers

It has to have the right molar solution.85. w/v. If you go over or under, the solution becomes hypotonic or hypertonic.
http://www.globalrph.com/hypertonic_saline.htm

2007-09-09 06:32:30 · answer #1 · answered by QuiteNewHere 7 · 0 0

It has to with osmotic pressure. If the saline concentration is below 0.85%, the concentration of water is higher outside than inside the cell, and water will diffuse into the cell until the pressure inside the cell causes it to burst. The opposite happens in stronger saline solutions. The cells will shrivel up (crenation) as water leaves the cell.

2007-09-09 06:38:33 · answer #2 · answered by Anonymous · 0 0

If I remember my chemistry, I don't think a RBC would burst in saline solution. In the body that would be an isotonic solution, and the cell would stay round. A cell would burst in distilled water (pure water with no salt concentration; hypotonic solution), and shrivel in salt water (more salt than water hypertonic solution).

2007-09-09 06:37:43 · answer #3 · answered by Ryann 2 · 0 0

The question you have asked is slightly wrong.

Firstly, one must know the concentration of the solution.If there is a high concentration, the RBC will shrivel due to exosmosis i.e. water exiting out of the cell.
If the concentration is low, it will burst due to endo osmosis i.e. water entering into the cell.

2007-09-09 06:29:05 · answer #4 · answered by artp1991 1 · 0 0

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