what is the derivative of y=square root x to the 3rd?

2 ⤊

2007-09-09 05:42:01 · 4 answers · asked by tlc 1 in Science & Mathematics ➔ Mathematics

y = x ^ (3/2)
dy / dx = ( 3 / 2 ) x ^ (1/2)
dy / dx = ( 3 / 2 )( √ x )

2007-09-09 07:04:38 · answer #1 · answered by Como 7 · 1⤊ 1⤋

y = x^(3/2)
y' = (3/2)x^(3/2 - 1) = (3/2)x^(1/2)

2007-09-09 12:46:37 · answer #2 · answered by sahsjing 7 · 1⤊ 1⤋

y = âxÂ³ = x^(3/2)
y = (3/2) x^(3/2 -1)
y = (3/2) x^(1/2)

2007-09-09 12:47:16 · answer #3 · answered by dr_no4458 4 · 0⤊ 3⤋

write it like this:
y = (âx)Â³ = â(xÂ³ ) either way you get x^3/2
y = x^ 3/2 = x^1.5
dy/dx = 1.5 x^.5 OR
dy/dx = 1.5âx

2007-09-09 12:47:20 · answer #4 · answered by 037 G 6 · 0⤊ 2⤋