find width & length for rectangular perimeter?

Question

The perimeter of a rectangular photograph is 36 cm. The length is 4 cm greater than the width. Find the width and the length.

Answer 1

Let's just set up an equation and solve. Let's call the width "W," so the length is equal to "W + 4." Now, we'll use the perimeter equation:

P = 2W + 2L
==> substitute the known perimeter and expression for length
36 = 2W + 2(W + 4)
==> distribute
36 = 2W + 2W + 8
==> subtract 8 from both sides and combine like terms
28 = 4W
==> divide both sides by 4
7 = W
==> the length is the width plus 4
L = 7 + 4 = 11

So, your answers are that width is 7 cm and length is 11 cm.

Answer 2

The perimeter is 2(w + l), where w is the width and l is the length.
l = 4+w
36 = 2(w + l)

Plug the 1st equation into the 2nd:

36 = 2(w + w + 4)
or
36 = 2(2w + 4)
or
36 = 4w + 8 // - 8

28 = 4w // divide by 4 and change sides

w = 7

Now, l = w + 4 = 7 + 4 = 11

Check the perimeter 2(w + l) = 2(7 + 11) = 2 * 18 = 36

Answer 3

Let W be the width. Length is W + 4 .
Perimeter is 2 ( W + W + 4 ) or 4W +8 = 36 or 4W = 28
W = 7 ; Length 11 cms. O.K.?

Answer 4

happy Belated New 365 days! :) I effective desire all is definitely. :) As on your question, this is somewhat effortless and easy: A rectangle has 4 sides, such that 2 of them are equivalent to a minimum of one yet another, jointly as the different 2 are equivalent to a minimum of one yet another. it somewhat is: ---- |O| ---- (be conscious: I had to insert the "O" so the gadget does no longer shift the "precise area" left!) In my determine, the precise & backside sides are equivalent to a minimum of one yet another, jointly as the left & precise sides are equivalent to a minimum of one yet another. So for a common rectangle, the fringe is caclulated in accordance to the formulation: Perimeter = 2*length + 2*Width it somewhat is: P = 2L + 2W Now, we are given: Width (W) = length (L) -- 8 ft. it somewhat is: W = L -- 8 ft We replace this into the perimter equation. We get: P = 2L + 2(L -- 8 ft) Simplifying yields: P = 2L + 2L -- sixteen ft P = 4L -- sixteen ft We additionally understand that the fringe measures 364 ft. for this reason we've: 4L -- sixteen ft = 364 ft next, we upload sixteen ft to the two sides. We get: 4L -- sixteen ft + sixteen ft = 364 ft + sixteen ft Simplifying yields: 4L = 380 ft L = ninety 5 ft considering the fact that we already understand that W = L -- 8 ft, we subtract 8 from the dimensions. That yields: W = L -- 8 ft W = ninety 5 ft -- 8 ft W = 87 ft. consequently, the rectangle measures ninety 5 ft by ability of 87 ft. Or, to place it yet in any different case: The rectangle has a length of ninety 5 ft and a width of 87 ft. I effective desire that replaced into as clean and powerful as you mandatory it to be. :) If no longer, i attempted my terrific, purely the comparable. :) sturdy success, take care and function an incredible day. :) Cheers! :)

Answer 5

L= W+4
P = 36 = 2L + 2W = 2(W+4) + 2W = 2W+8+2W = 4W + 8

36= 4W + 8
28 = 4W, W = 7.
L = 11

Answer 6

l = 4 + w
p = 2l + 2w
36 = 2(4 +w) + 2w
36 = 8 +2w + 2w
36 = 8 + 4w
28 = 4w
7 cm = w

l= 4 + w
l = 4 + 7
l = 11cm

Answer 7

Let w be width
Therefore, 2(w + (w+4)) = 36
w + w + 4 = 18
2w = 14
w = 7
Hence, width is 7cm and length is 11cm.