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A hawk is flying horizontally at 20.0 m/s in a straight line, 240 m above the ground. A mouse it has been carrying struggles free from its grasp. The hawk continues on its path at the same speed for 2.00 s before attempting to retrieve its prey. To accomplish the retrieval, it dives in a straight line at constant speed and recaptures the mouse 3.00 m above the ground.
Q: Assume no air resis, find diving speed. And what angle with horz during decent.

I got the time the mouse had until the hawk caught him again: 6.96 seconds

2007-09-09 04:43:20 · 1 answers · asked by ひいらぎ 5 in Science & Mathematics Physics

1 answers

s = (1/2)gt^2
t = √(2s/g) = √((2)237/9.9) = 6.9547s
Hawk flies 20.0m/s for 2s = 40m
Mouse falls in a parabolic path for 6.9547s:
Dist(horz mouse) = rt = 20(6.9547) = 139.093m
Subtract the 40m the hawk flew horz:
139.093 - 40 = 99.093m
Angle of descent from horz:
angle = arctan(237/99.093) = 67.3095degrees
Diving speed:
Time of dive:
6.9547 - 2 = 4.9547
Dist = √((237)^2 + 99.093)^2) = 256.882m
Speed:
speed = 256.882/4.9547 = 51.846m/s

2007-09-09 06:00:11 · answer #1 · answered by jsardi56 7 · 0 0

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