2007-09-09 04:40:21 · 6 answers · asked by key 2 in Science & Mathematics ➔ Mathematics
Modulus of a number is positive, therefore:-
| 6 - 2x | > 10
6 - 2x > 10
- 2x > 4
2x < - 4
x < - 2
6 - 2x < - 10
- 2x < - 16
2x > 16
x > 8
Answer is x < - 2 , x > 8
2007-09-13 00:40:42 · answer #1 · answered by Como 7 · 0⤊ 0⤋
x is any real number...
any absolute value is greater than or equal to zero..
therefore, it is always greater than a negative number...
also..
|6-2x| > -10
therefore,
6-2x > -10 or 6 - 2x < 10
x < 8 or x > -2
any number is either less than 8 or greater than -2
2007-09-09 04:47:22 · answer #2 · answered by Aaron 2 · 0⤊ 0⤋
its either (6-2x) > -10 or (6-2x) < -(-10)
so, 16>2x or -4<2x
so, x<8 or x>-2
2007-09-09 04:46:18 · answer #3 · answered by ʞzɹәႨnɹ 2 · 0⤊ 0⤋
squaring both sides to get rid of the modulus sign,
(|6-2x|)^2 > 100
36 -24x + 4x^2 > 100
9 - 6x + x^2 > 25
x^2 -6x -16 > 0
therefore
x>8 and x<-2
2007-09-09 05:16:25 · answer #4 · answered by abc 1 · 0⤊ 0⤋
Any absolute value is going to be greater than -10, so it's indeterminate. Just pull a number out of the air and plug it in. Then try another one.
2007-09-09 04:46:16 · answer #5 · answered by Anonymous · 0⤊ 0⤋
when removing the modulus signs the inequality becomes;
2007-09-09 04:58:20
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answer #6
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answered by orefilwe p 1
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+(6-2x)>-10........{1} and -(6-2x)>-10.............{2}
solving...{1}
6-2x>-10...add 2x both sides that becomes..6>2x-10
add 10 both sides 16>2x then divide by 2
x<8
solving....{2}
-6+2x>-10...add 6 both sides thaat becomes 2x>-4
divide both sides by 2
x<-2
final answer is -2